Model 5 Problems with Races Practice Questions Answers Test with Solutions & More Shortcuts
time & distance PRACTICE TEST [5 - EXERCISES]
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
Question : 6 [SSC CGL Tier-I 2016]
A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then A's speed is equal to:
a) 4 km/hr.
b) 7 km/hr.
c) 5 km/hr.
d) 3 km/hr.
Answer »Answer: (a)
Let, A's speed = x kmph.
B's speed = (7 - x) kmph
Time = $\text"Distance"/ \text"Speed"$
According to the question,
$24/x + 24/{7 - x} = 14$
$24({7 - x + x}/{x(7 - x)})$ = 14
${24 × 7}/{x(7 - x)}$ = 14
x (7 - x) = 12 = 4 × 3 or 3 × 4
x (7 - x) = 4 (7 - 4) or 3 (7 - 3)
x = 4 or 3
A's speed = 4 kmph.
Question : 7 [SSC SO 2007]
In a race of 1000 m, A can beat B by 100m. In a race of 400 m, B beats C by 40m. In a race of 500m. A will beat C by
a) 50 m
b) 60 m
c) 45 m
d) 95 m
Answer »Answer: (d)
When A runs 1000m, B runs 900m.
When A runs 500m, B runs 450 m.
Again, when B runs 400m, C runs 360 m.
When B runs 450m, C runs
= $360/400 × 450$ = 405 metres
Required distance
= 500 - 405 = 95 metres
Question : 8 [SSC CGL Tier-I 2016]
A and B start running at the same time and from the same point around a circle. If A can complete one round in 40 seconds and B in 50 seconds, how many seconds will they take to reach the starting point simultaneously ?
a) 200
b) 2000
c) 90
d) 10
Answer »Answer: (a)
Required time
= LCM of 40 and 50 seconds
= 200 seconds
Question : 9 [SSC CGL Tier-II 2015]
A is twice as fast as B, and B is thrice as fast as C is. The journey covered by C in 1$1/2$ hours will be covered by A in
a) 30 minutes
b) 10 minutes
c) 1 hour
d) 15 minutes
Answer »Answer: (d)
Time taken by C = t hours
Time taken by B = $t/3$ hours
and time taken by A = $t/6$ hours
Here, t = $3/2$ hours
∴ Required time taken by A
= $3/{2/6}$ hour = $1/4$ hour
= $(1/4 × 60)$ minutes = 15 minutes
Question : 10 [SSC CPO S.I.2007]
A runs twice as fast as B and B runs thrice as fast as C. The distance covered by C in 72 minutes, will be covered by A in :
a) 24 minutes
b) 12 minutes
c) 16 minutes
d) 18 minutes
Answer »Answer: (b)
Ratio of the speed of A, B and C = 6 : 3 : 1
Ratio of the time taken
= $1/6 : 1/3$ : 1 = 1 : 2 : 6
Time taken by A
= $72/6$ =12 minutes
IMPORTANT quantitative aptitude EXERCISES
Model 5 Problems with Races Shortcuts »
Click to Read...Model 5 Problems with Races Online Quiz
Click to Start..time & distance Shortcuts and Techniques with Examples
-
Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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